Sunday, September 25, 2011


Using a waveguide-to-coax adapter as an EMC antenna

Didier Juges, July 28, 1999


It is current practice to use a waveguide to coax adapter feeding a spectrum analyzer to check microwave equipment for RF leakage. While this is useful to pinpoint the origin of a leak if one is suspected, it is more difficult to use the readings to ascertain compliance to regulatory requirements such as MIL-STD-461 or Part 15 of FCC Rules.
To convert a power reading in dBm into a field strength in dBµV/m, the antenna factor of the device used must be computed.
The antenna factor is the term used in EMC testing to convert a voltage or power level fed by an antenna to an EMI analyzer into the field strength units (usually dBµV/m) of the electromagnetic field producing that voltage or power.
In a 50 ohm system, the antenna factor (expressed in dB(m-1)) of an antenna of absolute gain G (expressed in dB) at a wavelength L (expressed in meters) is:
    AF[dB(m-1)] = 19.8 - 20*log(L[m]) - 20*log(G[dB])
To convert a voltage reading V (expressed in dB(µV)) into an electric field E (expressed in dB(µV/m),) use the following formula:
    E[dB(µV/m)] = V[dB(µV)] + AF[dB(m-1)]
To convert a power reading P across a 50 ohm impedance (expressed in dBm) into an electric field E (expressed in dBµV/M,) use the following formula:
    E[dBµV/M] = P[dBm] + AF[dB(m-1)] + 107

Example:

Conventional wisdom has it that within its operating bandwidth, an open WR-90 waveguide adapter has a gain of approximately 7dB. Its antenna factor at 7.5 GHz (4.0 cm wavelength) is:     AF(dB(m-1)) = 19.8 - 20*log(0.04) - 20*log(7) = 30.9 dB
If we measure -70 dBm on the receiver/spectrum analyzer, the E field is:
    E = -70 + 30.9 + 107 = +67.9 dBµV/m

Reference:

John Osburn, EMC Antenna Parameters and Their Relationships, ITEM 1996 

source: http://www.ko4bb.com/Test_Equipment/EMI_Measurements.php

Sunday, September 11, 2011

What is a Decibel ?
Decibel is the unit used to express relative differences in signal strength.
Decibel is expressed as the base 10 logarithm of the ratio of the power of two signals : dB = 10 x Log10 (P1/P2)
Where Log10 is the base 10 logarithm and P1 and P2 are the powers to compare
(Log10 is different from Ln or LN = Neparian Logarithm, base e logarithm)
Signal amplitude can also be expressed in dB. Since power is proportional to the square of a signal's amplitude, dB is expressed as follows : dB = 20 x Log10 (V1/V2)
Where V1 and V2 are the amplitudes to compare
1 Bell (not really used in current) = Log10(P1/P2)
1 decibel (dB) = 1 Bell / 10 = 10 * Log10(P1/P2)
dBr = dB (relative) = dB = 10 * Log10(P1/P2)


base 10 Logarithm rules
Log10 (AxB) = Log10 (A) + Log10 (B)
Log10 (A/B) = Log10 (A) - Log10 (B)
Log10 (1/A) = - Log10 (A)
Log10 (0,01) = - Log10 (100) = -2
Log10 (0,1) = - Log10(10) = - 1
Log10 (1) = 0
Log10 (2) = 0,3
Log10 (4) = 0,6
Log10 (10) = 1
Log10 (20) = 1,3
Log10(2 x 10) = Log10(2) + Log10(10) = 1 + 0,3
Log10 (100) = 2
Log10 (1 000) = 3
Log10 (10 000) = 4


Logarithm and dB (decibel)
Power Ratio dB = 10 x log10 (Power Ratio)
AxBx dB = 10 x Log10(A) + 10 x Log10(B)
A/Bx dB = 10 x Log10(A) - 10 x Log10(B)
1/Ax dB = + 10 x Log10(1/A) = - 10 x Log10(A)
0,01- 20 dB = - 10 x Log10(100)
0,1- 10 dB = 10 x Log10(1)
10 dB = 10 x Log10(1)
23 dB = 10 x Log10(2)
46 dB = 10 x Log10(4)
1010 dB = 10 x Log10(10)
2013 dB = 10 x (Log10(10) + Log10(2))
10020 dB = 10 x Log10(100)
1 00030 dB = 10 x Log10(1 000)
10 00040 dB = 10 x Log10(10 000)



dBm = dB milliwatt = 10 x Log10 (Power in mW / 1 mW)
Power Ratio dBm = 10 x
Log10 (Power in mW / 1 mW)
1 mW1 mW / 1 mW = 10 dBm = 10 x Log10(1)
2 mW2 mW / 1 mW = 23 dBm = 10 x Log10(2)
4 mW4 mW/1mW=46 dBm = 10 x Log10(4)
10 mW10 mW/1mW=1010 dBm = 10 x Log10(10)
0,1 W100 mW/1mW=10020 dBm = 10 x Log10(100)
1 W1000 mW/1mW=100030 dBm = 10 x Log10(1 000)
10 W10 000mW/1mW=10 00040 dBm = 10 x Log10(10 000)


dBW = dB Watt = 10 x Log10 (Power in W / 1 W)
Power Ratio dBW = 10 x Log10 (Power in W / 1 W)
1 W1 W / 1 W = 10 dBW = 10 x Log10(1)
2 W2 W / 1 W = 23 dBW = 10 x Log10(2)
4 W4 W / 1 W = 46 dBW = 10 x Log10(4)
10 W10 W / 1 W = 1010 dBW = 10 x Log10(10)
100 mW0,1 W / 1 W = 0,1-10 dBW = -10 x Log10(10)
10 mW0,01 W / 1 W = 1/100-20 dBW = -10 x Log10(100)
1 mW0,001W/1W=1/1000-30 dBW = -10 x Log10(1000)


Power/Voltage Gain
dB Power Ratio Voltage Ratio dB Power Ratio Voltage Ratio
01,001,00
1010,003,16
11,261,12
1112,593,55
21,581,26
1215,853,98
32,001,41
1319,954,47
42,511,58
1425,125,01
53,161,78
1531,625,62
63,982,00
1639,816,31
75,012,24
1750,127,08
86,312,51
1863,107,94
97,942,82
1979,438,91
1010,003,16
20100,0010,00


Attenuation (dB) = 10xLog10(Pin/Pout) = 20xLog10(Vin/Vout)
Gain (dB) = 10xLog10(Pout/Pin) = 20xLog10(Vout/Vin)
Gain (dB) = - Attenuation (dB)

Power (W) = voltage (V) x Voltage (V) x Z (Ohm) = V x V / Z = V x I
So Gain(dB) = 10 x Log10(Pout/Pin) = 10 x Log10((Vout x Vout / Zout) / (Vin * Vin / Zin))
if Zin = Zout, Gain(dB) = 10 x Log10(Vout x Vout / Vin /Vin) =
10 x (Log10(Vout / Vin) + Log10(Vout / Vin)) = 10 x 2 x Log10(Vout / Vin) = 20 x Log10(Vout / Vin)
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